空气比热容比测定实验的数据分析
$$ U_{dA}=\sqrt{\frac{\sum((d_i-\bar{d}))^2}{n(n-1)}}=0.008mm ,\ U_{dB}=\frac{0.004}{\sqrt{3}}mm $$
$$ U_d=\sqrt{U_{dA}^2+U_{dB}^2} = 0.008mm ,\ U_{rd}=\frac{U_d}{d} *100\%= 0.06\% $$
d = 13.707 ± 0.008mm
m = 11.18g
仪器误差Δ = 0.10g
$$ U_m=\frac{\Delta}{\sqrt{3}} = 0.06g,\, U_{rm}=\frac{U_m}{m}*100\%=0.5\% $$
m = 11.18 ± 0.06g
V = 2.25L = 2.25 * 10−3m3
$$ U_v = 0.0020*10^{-3}m^3,\, U_{rV}=\frac{U_V}{V}*100\%=0.09\% $$
V = (2.25 ± 0.0020) * 10−3m3
实验开始时:pL1 = 101.6kPa,实验结束时:pL2 = 101.6kPa
平均值$ p_L=101.6kPa $
仪器误差Δ = 0.01kPa
$$ U_{P_L} =\frac{\Delta}{\sqrt{3}} = 5*10^{-3}kPa, U_{rp_L}=\frac{U_{p_L}}{p_L}*100\%=5*10^{-3}\% $$
pL = 101.6 ± 0.005kPa
$$ p=p_L+\frac{4mg}{\pi d^2} = 102.3kPa$$
$$U_p\approx U_{p_L}=5*10^{-3}kPa,\, U_{rp}=\frac{U_p}{p}*100\%=5*10^{-3}\% $$
p = 102.3 ± 0.005kPa
$$ U_{TA} = \sqrt{\frac{\sum (T_i-\bar{T})^2}{n(n-1)}} = 3.9*10^{-5}s,\, U_{TB}=\frac{0.1}{100}s=0.0010s $$
$$ U_T=\sqrt{U_{TA}^2+U_{TB}^2}=1.0*10^{-3}s,\, U_{rT}=\frac{U_T}{\bar{T}}*100\%=0.18\% $$
T = 0.5428 ± 0.001s
$$ \gamma = \frac{4mV}{T^2pr^4}=\frac{64mV}{T^2pd^4}=1.524 $$
$$ U_{r\gamma} = [U_{rm}^2+U_{rv}^2+(2U_{rT})^2+U_{rp}^2+(4U_{rd})^2]^{\frac{1}{2}} = 0.8\% $$
Uγ = γUrγ = 0.012
实验结果表达式:$ = 1.524 $
γ0 = 1.402
$$ E_0=\frac{|\gamma-\gamma_0|}{\gamma_0}*100\%=8.7\% $$